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9a^2+15a=0
a = 9; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·9·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*9}=\frac{-30}{18} =-1+2/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*9}=\frac{0}{18} =0 $
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